Virat Kohli played a crucial role as India defeated Australia by four wickets in the first semifinal of the ICC Champions Trophy 2025, held on March 4 at the Dubai International Cricket Stadium. Kohli scored 84 runs off 98 balls, marking his 74th ODI half-century and leading India to a successful chase of 265 runs.
Australia batted first after winning the toss, setting a target of 264 runs. They were all out in 48.1 overs, with Steve Smith top-scoring with 73 runs from 96 balls. Mohammed Shami was the standout bowler for India, taking 3 wickets for 48 runs in his 10 overs. Indian spinners Varun Chakravarthy and Ravindra Jadeja also made significant contributions, each claiming two wickets.
In response, India faced early setbacks, losing Shubman Gill for just 8 runs and Rohit Sharma for 28. However, Kohli and Shreyas Iyer steadied the innings with a vital partnership of 91 runs. Iyer contributed 45 runs off 63 balls, anchoring the chase alongside Kohli. Lokesh Rahul finished the match with an unbeaten 42 runs off 34 balls, helping India reach a total of 267 runs for the loss of 6 wickets.
Kohli’s performance was pivotal, as he kept the required run rate manageable and guided the team through tense moments. He expressed that maintaining composure under pressure is key in such high-stakes matches. His dismissal in the 43rd over raised concerns, but Rahul and Hardik Pandya ensured the win was secured without further drama.
India’s victory not only sends them to the final but also marks the highest chase against Australia in an ICC event. The final will take place in Dubai, where India will face the winner of the second semifinal between South Africa and New Zealand, scheduled for March 5 in Lahore, Pakistan.
Overall, India’s performance showcased their depth and resilience, setting the stage for a thrilling final in the tournament.